Re: Scripting/Information Help
From: Provoost, Richard (Richard.Provoost_at_ESSENT.NL)
Date: 03/25/04
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Date: Thu, 25 Mar 2004 14:09:51 +0100 To: aix-l@Princeton.EDU
Terry,
Here an ugly but functional oneliner:
lsuser -a time_last_login ALL | grep time_last_login | awk -F'=' '{ if
(1080133450-$2 > 86400*180) print $0}'
Where 1080133450 is the time somewhere of today in seconds from root or
anybody like: lsuser -a time_last_login root
180 is days and 86400 is nr seconds a day
If it works it gives back an ugly list of users that haven't login since 180
days !!
HTH,
Richard.
-----Oorspronkelijk bericht-----
Van: terry.german@PHONES4U.CO.UK [mailto:terry.german@PHONES4U.CO.UK]
Verzonden: donderdag 25 maart 2004 13:37
Aan: aix-l@Princeton.EDU
Onderwerp: Scripting/Information Help
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Guru's,
As I am not a wizz on scripting I was just wondering if anyone out there can
help me.
I want to find out which users on our M80 running AIX 4.3.3 have not
accessed there id for the last 6 months?
If anyone could help it would be great...
Thanks
Terry German
AIX System Administrator
IBM Certified Specialist - AIX
Phones 4u Limited
Swift House
Liverpool Road
Newcastle Under Lyme
ST5 9JJ.
[E] terry.german@phones4u.co.uk
<mailto:terry.german@phones4u.co.uk <mailto:terry.german@phones4u.co.uk> >
[T] +44 (0)1782 600783
[M] +44 (0)7748908609
[F] +44 (0)1782 587192
[W] http://www.phones4u.co.uk <http://www.phones4u.co.uk>
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- Previous message: Bullerwell, Edward: "Re: Scripting/Information Help"
- Maybe in reply to: terry.german_at_PHONES4U.CO.UK: "Scripting/Information Help"
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