Re: grep question

From: Sunder Iyengar (Sunder.Iyengar_at_VERITAS.COM)
Date: 03/25/05

  • Next message: Jim Richard: "Re: IBM FastT vs. EMC Clarion" 
    Date:         Fri, 25 Mar 2005 10:29:30 +1100
To: aix-l@Princeton.EDU

    John,

    If the string to be searched is "abc" in the following file (listing
    below), as per your stated rules (ignore string in the first 8
    characters), then the grep would be as follows.

    # cat sample
    abc1552uenkd
    776wabc288e8e
    12345678abc2663
    7831687138abcjdoiewd
    abdabc3791u312ew1jeo
    dgsaiudadgagdagabc
    1234567abc366dj

    # grep '^.........*abc' sample
    12345678abc2663
    7831687138abcjdoiewd
    dgsaiudadgagdagabc

    Hope this helps.
    Explanation -

    ^=beginning of line
    .=any character
    After a string of 8 . (dots), the ninth . followed by * says zero or
    more characters.

    Sunder.

    -----Original Message-----
    From: IBM AIX Discussion List [mailto:aix-l@Princeton.EDU] On Behalf Of
    John Dunn
    Sent: Friday, 25 March 2005 2:42 AM
    To: aix-l@Princeton.EDU
    Subject: grep question

    I want to search for a lines matching a string in a file, but ignore
    the first 8 characters in each line in the search. However I do not want
    to remove the first 8 characters from the file.

    Can I do this with grep?

    John

  • Next message: Jim Richard: "Re: IBM FastT vs. EMC Clarion"

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