Re: egrep question

Denny,

I'm not sure what you mean by quoted.



If you mean display quotes, then it is:

32 echo '"'$name'"' " is IN "$2



If you mean quote it to the shell, so the echo command receives $name as
one argument with spaces and special characters, then it is:

32 echo "$name" " is IN "$2

or
32 echo "$name is IN $2"



If you want both, then you can use:

32 echo "\"$name\"" " is IN "$2

or
32 echo "\"$name\" is IN $2"





Edward.Davignon@xxxxxxxxxxxxxx
Lead Analyst - Distributed Systems
Utility Shared Services - IT
Energy East Corporation
Office Phone: (585) 771-4952

________________________________

From: IBM AIX Discussion List [mailto:aix-l@xxxxxxxxxxxxx] On Behalf Of
Denny Watkins
Sent: Wednesday, February 07, 2007 9:13 AM
To: aix-l@xxxxxxxxxxxxx
Subject: egrep question



I have two files which have titles of books.
I want to check the book titles in one file to see if the title is in
the other file.
The book titles have spaces, periods, etc.



I wrote a script but I am having a problem getting the title in a form
to 'egrep' to the other file.
Titles examples are like:
Tom Sawyer
Tale Of Two Cities




Script is called "check.file.to.file" and is as follows
and is run check.file.to.file name-of-file-1 name-of-file-2



1
2 if [ "$1" = "" ]
3 then
4 arg=0
5 echo "No args..Args are file-name file-to-check"
6 exit
7 else
8 arg=1
9 file1=$1
10 fi
11
12 if [ "$2" = "" ]
13 then
14 echo "Need 2nd argument for file-to-check"
15 exit
16 else
17 file2=$2
18 fi
19
20 # for name in `cat $file1 | cut -f1 -d' '`
21
22 for name in `cat $file1`
23 do
24
25 # egrep -w $name $2 > /dev/null
26 egrep $name $2 > /dev/null
27 grepresult=$?
28
29
30 if (($grepresult == 0))
31 then
32 echo $name " is IN "$2
33 # egrep -w $name $2
34 else
35 echo $name " NOT in "$2
36 fi
37
38 done



Is seems the problem is at line 32. How do you make the $name variable
in line 32
quoted?



Thanks,



Denny Watkins
Morningside College
Phone: 712-274-5250



Email: watkins@xxxxxxxxxxxxxxx

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