Re: The 'ln -s' command

I tried the 'ln -s' command in bothe 4.3 & 4.7 in a
situation where it should fail and it did, but it still had
a return/exit code of 0 , I think it should have been
nonzero. I tried 'ln -s a b' where the file b existed
(and was a directory) and I wanted to create the file named
a also pointing to it. The correct form was 'ln -s b a'.


FreeBSD 4.3-RELEASE FreeBSD 4.3-RELEASE #0: Sat Apr 21 \
10:54:49 GMT 2001 \
jkh@xxxxxxxxxxxxxxxxx:/usr/src/sys/compile/GENERIC i386

FreeBSD 4.7-RELEASE FreeBSD 4.7-RELEASE #0: Wed Oct 9 \
15:08:34 GMT 2002 \
root@xxxxxxxxxxxxxxxxxxxxxxx:/usr/obj/usr/src/sys/GENERIC \
i386

I don't have a 4.3 or 4.7 box, but on 4.11 I see:

$ ls a.out
a.out
$ ln -s foo a.out
ln: a.out: File exists
$ echo $?
1

Are you really running /bin/ln? Do you run other programs
at the time of displaying your PS1 prompt?

--
FreeBSD Developer, http://people.freebsd.org/~jkoshy
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