Re: scsi raid geometry high-point rocketraid 1640

On Mon, Apr 30, 2007 at 09:54:04AM +0200, Klaus Friis Østergaard wrote:

2007/4/30, Jerry McAllister <jerrymc@xxxxxxx>:


Hi,

I have a raidcontroller high-point 1640 with 4 disks of 400 GB in a raid
5
array given me 1200 GB. The bios utility of the controller zero build
the
array with 64 kb

FDISK says that the geometry is 145923/255/63 and it is incorrect. Then
it
says that for scsi it is the translation mode the raid controller is
using.

Usually you want to accept what fdisk does. Just make the slices
that you want. Geometry is virtual on these systems.


How do I find this?

If I continue with the defaults I only get 1144654 MB like missing 100
GB.

Well, I would expect you to get something less than 1,490 GB just from
the difference between the manufacturer use of GB (1,000,000,000 Bytes)
and the way the OS uses GB (1,073,741,824 Bytes).


That is the missing link, the raid controller says 1200 GB if recalculated,
using 1.073741824 it gives 1,117.59 GB multiplied by 1024 it gives
1144409 MB which is what FDISK gives default.

Wow. Don't tell me I got one (out of how many?).
I shall celebrate.

////jerry



I don't know how much the raidcontroller eats up to manage
the raid. Raid 5 takes a piece for its redundancy/error
correction. A raid 5 would eat at least 20% and maybe up to 30% if it
is rather inefficient.


WIth 4 disks it is 25% as 4th disk make the redundancy.

After that you will lose some because of inconvenient remnants of space
that doesn't get used. Then, there are amounts for superblocks and other
aspects of building a filesystem, etc. I think that tends to be around
10%
altogether.

So, your number seems somewhat probable, offhand, without detailed
calculations.

What operations did you do to get to that point? Mine would be an
fdisk that makes one slice of the entire device, a bsdlabel that
divides the slice in to about 6 partitions (including swap) and
a newfs on each partition except swap.


I only need the array only for one big slice and one partition for data
storage.


Thanks for the help
--
Klaus F. Østergaard, <farremosen(at)gmail dot com>
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