awk question

Len Conrad <lconrad@xxxxxxxxxxxxx> wrote:

We need to print a line when the 3rd field (with trailing ";"
delimiter) is, eg, exactly 5 lower case characters

awk ' $3 ~ /^[a-z]{5,5};$/ {print $0} ' file

... doesn't work.

If ";" is the delimiter character, you need to tell awk
about it (i.e. use the -F option). This one should work:

awk -F';' '$3 ~ /^[a-z]{5}$/ {print}' file

If that still doesn't work for you, please specify your
file format more exactly, and provide an example of the
input lines.

Best regards
Oliver

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