Re: Understanding DSL10L cabinet/hardware


"Tad Winters" <stafford.no.spam.winters2@xxxxxxxxxxx> wrote in message
news:Xns98D56EFA5B5EBstaffordnospamwinter@xxxxxxxxxxxxxxxx
<snip>
Load the bay with a bank of LEDs that indicate nothing. They can flash or
not.
<snip>
They don't need to produce any extra heat.


Don't think so. The LEDs would likely have to use as much current as the
resistor, for the same reason - to keep the PSU load current in the "safety
zone" where the PSU works OK. If they use as much current as the
resistor/dummy load, and at the same voltage, then they're going to generate
pretty much the same amount of heat - being LEDs, some of the input power
will initially come out as light but it pretty much all ends up as heat
sooner or later, ye canna change the laws of physics cap'n.

Some way of sensing the actual genuine load current, and reducing the
current through the resistor to keep the excess power to the minimum
required, might be helpful. In the absence of details of the circuit, might
that even be what's occuring? In a heavily loaded DS10L, the resistor isn't
required, does nothing and therefore runs cool, whereas in a lightly
configured DS10L, the resistor has to dump a few excess watts to keep the
PSU operating happily? Who knows...


.

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