Re: How to sort the output from find

From: Chris F.A. Johnson (c.f.a.johnson_at_rogers.com)
Date: 09/22/03

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    Date: 21 Sep 2003 22:35:38 GMT

    On Sun, 21 Sep 2003 at 11:16 GMT, Andreas Kahari wrote:
    > In article <3F6D79BE.7000303@jpl.nasa.gov>, Julia Bell wrote:
    >> I'm using "find" to find a set of filenames that include a particular
    >> string. But, then I need a way to sort that list by date (ls -lrt of
    >> all the files that would found).
    >>
    >> Is there a straightforward way to do that?
    >
    > For a moderate number of files, this wil probably do it:
    >
    > find /some/path -type f -name "pattern" -print | xargs ls -lrt
    >
    > I say "moderate" since if 'find' finds too many files for one
    > single invocation of 'ls', it will invoke it twice or more
    > times. The files listed by 'ls' in one invocation will be
    > sorted the way you want.

        Then why use xargs? If the number is small enough for a single
        invocation of ls by xargs, it should be small enough to work as
        args to ls.

    ls -lrt `find /some/path -type f -name "pattern" -print`

        If you are using GNU find, you can format the output to your
        liking and just pipe it to sort. "man find /printf" for more
        details. 

    -- 
    Chris F.A. Johnson                        http://cfaj.freeshell.org
    ===================================================================
    My code (if any) in this post is copyright 2003, Chris F.A. Johnson
    and may be copied under the terms of the GNU General Public License
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