argv[0] in execvp()

From: Alex Vinokur (alexvn_at_users.sourceforge.net)
Date: 11/26/05 

Date: 25 Nov 2005 21:30:18 -0800

QUOTES from http://www.mkssoftware.com/docs/man3/execl.3.asp

----------------------------------------------------
int execvp(const char *file, char *const argv[])

argv
Is the argument list for the new process image. This should contain an
array of pointers to character strings, and the array should be
terminated by a NULL pointer. The value in argv[0] should point to a
file name that is associated with the process being started by the
exec() function.
-----------------------------------------------------

Why should 'argv[0]' point to a file name?
Is not it enough the 'file' parameter to execute the program?

Alex Vinokur
     email: alex DOT vinokur AT gmail DOT com
     http://mathforum.org/library/view/10978.html
     http://sourceforge.net/users/alexvn

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