Re: "make all" does not make all!

Johs32 <dfgdg@xxxxxxx> writes:
I have this makefile:

all: qsort1 qsort2 test

test :
cd test && $(MAKE) test

qsort1 :
cd gopgave/g1/opg1 && $(MAKE) qsort1

qsort2 :
cd gopgave/g1/opg2 && $(MAKE) qsort2

[...]
why does it never call "test"?

Because test is an existing file with no dependencies, and is
therefore always up to date.

BTW, it won't kill you to RTFM before asking questions on Usenet.

DES
--
Dag-Erling Smørgrav - des@xxxxxx
.