Re: Makefile Rule: idl/%.idl -> src/%.c

On Wed, 26 Apr 2006 13:31:26 -0700, Maxim Yegorushkin wrote:


Michael B Allen wrote:
If I compile an idl file to produce a c file with a command like:

$ idlc -o src/foo idl/foo.idl

this will generate a src/foo.h and src/foo.c file.

My question is, given a list of idl files (or perhaps just the names like
'foo') can I create a single Makefile target to generate these files?

I was thinking of something like:

IDL = idl/foo.idl idl/bar.idl idl/zap.idl

.SUFFIXES: .idl

.idl.c:
idlc -o src/$* $<

but of course $* would be wrong and regardless the rule doesn't even
match:

$ make src/foo.c
make: *** No rule to make target `src/foo.c'. Stop.

Any ideas?

I am no expert in makefiles, but something like this you might find of
help:

idl := a.idl b.idl
idl_c := $(idl:.idl=.c)
idl_h := $(idl:.idl=.h)

all: $(idl_c) $(idl_h)

idl_cmd := cp

%.h: %.idl
$(idl_cmd) $< $@

%.c : %.idl
$(idl_cmd) $< $@

clean:
rm *.{c,h}

.PHONY: clean

Yeah, that helps. Two issues remain. One is creating the .h and .c
output in the src/ directory. For this I suppose a simple

mv $(IDL_C) $(IDL_H) src/

would suffice. But I still need to address the .o files for linking. For
that I'm thinking I can use subst like:

IDL2SRC = $(subst idl/,src/,$(IDL))
OBJS = $(SRCIDL:.idl=.o)

but I have to wonder if this is portable.

Mike

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