Re: getting date from timestamp

In article <1159458333.353715.103030@xxxxxxxxxxxxxxxxxxxxxxxxxxxx>,
"pawan_test" <sridhara007@xxxxxxxxx> wrote:

Hi All,

i have a time stamp. from that i am trying to awk to get the year,
month and date.

TIME=20060614092446

DESIRED OUTPUT: 20060614

i am doing the following;

TIME=20060614092446
$ TimeStarted=`expr match '$TIME' '.*\(......\)'`
echo $TimeStarted

i am not getting any output. can anyone please suggest me.

Single quotes prevent variable expansion, use double quotes.

Also, your regular expression is incorrect, it should be '^\(........\)'
to get the first 8 characters -- your expression will grab the last 6
characters.

You can also do this without regular expressions at all, just shell
variable substring syntax:

TimeStarted=${TIME:0:8}

--
Barry Margolin, barmar@xxxxxxxxxxxx
Arlington, MA
*** PLEASE post questions in newsgroups, not directly to me ***
*** PLEASE don't copy me on replies, I'll read them in the group ***
.

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