Re: regexp

From: Stephane CHAZELAS (this.address_at_is.invalid)
Date: 10/31/03 

Date: Fri, 31 Oct 2003 19:46:40 +0100

2003/10/31, 10:46(-06), Kumar Sundaram:
> How do a get a regexp to match the data given below in a find statement. I
> use a * at the end and it maches a number or nothing.
>
> for script in `find /home/xxx -name "send[a-d][a-z][a-z]*" -print`
> do
> echo "$script"
> nohup $script &
> echo "$script executed"
> done

I'm not sure to understand your question. Does this somehow
answer your question:

find /home/xxx -type f -perm -111 \( \
  -name 'send[a-d][a-z][a-z]' -o \
  -name 'send[a-d][a-z][a-z][0-9]' \) -exec sh -c '
    printf %s\\n "$1"
    nohup "$1" &
    printf "%s started in background\n" "$1"' {} {} \;

-name argument is not a regexp but a wildcard, see man fnmatch
for how to use wildcards.

-perm 111
is a check to see if the file is executable. Note that it just
checks wether everyone has execute permission for it. That's an
approximation. Better solution could be:

find /home/xxx -type f -perm +111 \( \
    -name 'send[a-d][a-z][a-z]' -o \
    -name 'send[a-d][a-z][a-z][0-9]' \) -exec sh -c '
      [ -x "$1" ] || exit 1
      printf %s\\n "$1"
      nohup "$1" &
      printf "%s started in background\n" "$1"' {} {} \;

Unfortunately, find has not option to check if *you* (the user
running find) have the right to execute a given file. 

-- 
Stéphane                      ["Stephane.Chazelas" at "free.fr"]

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