Help w/ matching grep and regular expressions

From: WH (nos.pam_at_email.com)
Date: 03/11/04 

Date: Thu, 11 Mar 2004 03:18:25 GMT

I'm doing an assignment for a unix class, but I'm stuck on two questions.

3. Write a command that removes all files that end in a ".log" extension,
and do not contain the string "west". Remove them form your home directory,
and all subdirectories, recursively.

4. Write a command that produces the 'ls -l" output for the current
directory, but only lists files and directories for which the "other"
category (as opposed to "user" and "group" has execution permission.

With number 3, if I ignore the part about west, I would do a

 find . -name *.log | xargs rm

But with the west there, I know I want to grep it, and have grep say
something like "match all lines except those with 'west'" but I can't figure
out how to do it. I scoured the web for an hour, and all I could find for
"except" was the ^carrot, which is useless here.

With number four, since permissions always have ten characters, I'd want to
match anything w/ ten characters, ending in x. I've got no idea how to
match the end of a word, just the end of a line w/ $.

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