Re: Extract specific date in a directory and send output through email

From: Barry Margolin (barmar_at_alum.mit.edu)
Date: 08/14/04

  • Next message: Alan Connor: "Re: Extract specific date in a directory and send output through email" 
    Date: Sat, 14 Aug 2004 00:59:56 -0400

    In article <69e9ce57.0408131902.7a399fb8@posting.google.com>,
     davidludeman@cox.net (DaveL) wrote:

    > Greetings folks...need some help.
    >
    > Here is the current script that I have:
    >
    > This first line is fine and it pulls the entire file strucutre in the
    > directory:
    >
    > ls -lrt /bs/processing/* >> jess1.txt
    >
    > However, my problem is i only need the current days data, today.
    >
    > I thought i could use this:
    >
    > dateM='date | cut -c 5-10'
    > cat jess1.txt ls -lartR |grep "$dateM" >> jess2.txt
    >
    > But this is not pulling out anything.
    >
    > please help....

    You have to use backticks, not quotes, in the variable assignment
    statement:

    dateM=`date | cut -c 5-10`

    But it would be even better to use date's formatting option rather than
    cut:

    dateM=`date '+%b %e'` 

    -- 
Barry Margolin, barmar@alum.mit.edu
Arlington, MA
*** PLEASE post questions in newsgroups, not directly to me ***
  • Next message: Alan Connor: "Re: Extract specific date in a directory and send output through email"

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