Re: What does this 'sort' command line do?

From: Dr. Yuan LIU (yliu_at_stemnet.nf.ca.remove_this)
Date: 06/10/03

  • Next message: Jeff Weeks: "how to replace multiple lines in a file?"
    Date: Tue, 10 Jun 2003 03:32:18 GMT
    
    

    Kenny McCormack wrote:
    > In article <g29Fa.23$h8.243@paloalto-snr1.gtei.net>,
    > Barry Margolin <barry.margolin@level3.com> wrote:
    >
    >>In article <bc34eu$lfo$1@yin.interaccess.com>,
    >>Kenny McCormack <gazelle@interaccess.com> wrote:
    >>
    >>>Consider this:
    >>>
    >>> sort -T . -n +0.1 -0.16 +0.87 -0.92 +0.92 -0.94 +0.94 -0.96
    >>>
    >>>As far as I can tell, in my testing, it is a NO-OP. Please comment.
    >>
    >>It sorts the standard input using the following numeric keys in order of
    >>priority: columns 1-15, columns 87-91, columns 92-93, finally columns
    >>94-95. Since you're using old-style syntax, column numbering starts from
    >>0.
    >>
    >>Why do you think it's a no-op?
    >
    >
    > Experience running the above command, of course.
    >
    > Does the following sway your vote any:
    >
    > --- Cut here ---
    > % cat /tmp/zzz
    > the
    > quick
    > brown
    > fox
    > jumps
    > over
    > the
    > lazy
    > dog

    Nope. If the data doesn't even contain that many columns, how do you
    expecte it to make a difference?

    Yuan Liu

    > % sort +0.1 -0.10 !$
    > sort +0.1 -0.10 /tmp/zzz
    > lazy
    > the
    > the
    > dog
    > fox
    > brown
    > quick
    > jumps
    > over
    > % ^1^0
    > sort +0.0 -0.10 /tmp/zzz
    > brown
    > dog
    > fox
    > jumps
    > lazy
    > over
    > quick
    > the
    > the
    > %
    > --- Cut here ---


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