Re: copy a directory recursively without data/files

From: Michael Tosch (eedmit_at_NO.eed.SPAM.ericsson.PLS.se)
Date: 07/29/04 

Date: 29 Jul 2004 14:00:50 GMT

In article <slrncghi5o.1rg.stephane.chazelas@spam.is.invalid>, Stephane CHAZELAS <this.address@is.invalid> writes:
...
>
> > Question: while perfectly captured by the two '{}',
> > why is the first '{}' in Solaris $0 and not $1?
>
> Why not? It's what POSIX requires, and what most shells do.
>

I see that

#!/bin/sh
echo $0 $1

returns its invocation name and the first argument,

while

sh -c 'echo $0 $1' arg1 arg2

returns arg1 arg2.

So if this is always the case, one could rewrite

find . -type d -exec env d="$dest_root" sh -c '
  exec mkdir -p -- "$d/$1"' '{}' '{}' \;

always as

find . -type d -exec env d="$dest_root" sh -c '
  exec mkdir -p -- "$d/$0"' '{}' \; 

-- 
Michael Tosch
IT Specialist
HP Managed Services
Technology Solutions Group
Hewlett-Packard GmbH
Phone: +49 2407 575 313
Mail: michael.tosch:hp.com

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