Re: Awk Question - Again
From: Christoph Gysin (fr33z3_at_gmx.ch)
Date: 10/29/04
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Date: Fri, 29 Oct 2004 16:59:43 +0200
Christoph Gysin wrote:
> How about:
> name=`echo $label1 | awk '{print($1)}'`
Or even simpler:
name=${label1%% *}
Christoph
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