Re: Adding to the command line via variables

G_r_a_n_t__at_dodo.com.au
Date: 07/30/05

  • Next message: Bill Marcum: "Re: Adding to the command line via variables" 
    Date: Sun, 31 Jul 2005 00:46:11 +1000

    On Sat, 30 Jul 2005 15:29:42 +0100, "John L" <jl@lammtarra.notthisbit.fslife.co.uk> wrote:
    >
    > "Jeff Kloek" <Jeff@Kloek.com> wrote in message news:DHLGe.42172$B52.25467@tornado.ohiordc.rr.com...
    > > Hello. I'm trying to figure out how I can build a command line using the
    > > output of the ls |grep command. The problem is the number of files returned
    > > will vary.
    > > As an example, one time might find output1, output2 and output3, and another
    > > time it might also include output4 and output5.
    > >
    > > How can I use the output of "ls |grep output" to build a command line that
    > > does the following:
    > > lp -d printername outputX outputX outputX ?
    > > I don't expect to ever exceed the allowable count of command line
    > > parameters.
    > > Any ideas would be greatly appreciated!!
    >
    > In general, you could use command substitution or xargs
    > but in this case, do you need the "ls |grep" at all?
    >
    > lp -d printername output*
    or:

      for x in some_pattern; do some_stuff_to $x; done

    Grant.

  • Next message: Bill Marcum: "Re: Adding to the command line via variables"

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