Re: get the first word of a file


dufffman@xxxxxxxxx wrote:
> Hi,
>
> I have a data file of the format
>
> 20051112|data|moreData|evenMoreData|..|
> 20051112|data|moreData|evenMoreData|..|
> 20051112|data|moreData|evenMoreData|..|
> 20051112|data|moreData|evenMoreData|..|
> 20051112|data|moreData|evenMoreData|..|
> 20051112|data|moreData|evenMoreData|..|
> 20051112|data|moreData|evenMoreData|..|
>
>
> its going to be a pipe delimited file, w/the only the first date beng
> the constant. in unix which command would i write to extract the first
> '20051112' out of this file?
>
> Thanks,

Greetings,

I am not quite sure what you are asking.

#to obtain the FIRST DATE ONLY
cat data | sed s/\|.*// | head -1

#to obtain all the dates
cat data | sed s/\|.*//

# to remove all the dates
cat data | sed s/[0-9]*\|// > $$ ; mv $$ data

Hope this helps,
William

.

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