Re: capture output of an ldapmodify command
- From: "johngnub" <johngnub@xxxxxxx>
- Date: 25 Sep 2006 16:14:17 -0700
Sorry to ask the silly questiions, a few things to check out.
- Sure you have the right path? Ie try the full pathing to the comand.
- Do a df, make sure did not use up all your space before you start
your log....
- Simple re-direct, /home/fun/foo.sh 2> /tmp/foo.err.log 1>
/tmp/foo.err.log
- Does that user have the rights to the dir.
Ok, some thing I do, example useing fun, in ur case
echo "fun" |grep fun && echo "Found fun"
Or
echo "foobar" |grep fun || echo "no fun"
But, in your example, I see two lines, Is that the issue problem?
? What does norm output look like ?
2 cents, JB...
Anton wrote:
hello- Im encountering a strange problem Im sure Im overlooking the
problem....
i am performing an ldapmodify command on an ldif file and want to
capture the output:
IE: this is what is seen on the command line:
modifying entry: entryname
ldap_modify: object exists
modifying entry: entryname
ldap_modify: no such object
***************************************
I want that EXACT output to be piped into a file--- BUT no matter what
I do i get a file that looks like this:
modifying entry: entryname
modifying entry: entryname
ldap_modify: object exists
ldap_modify: no such object
the above occurs when i direct stderr and stdout to the same file-- so
Im assuming stdout is being reported all at once then the stderr... is
there a way I can just capture the output like you see on the screen
when running the ldapmodify command?
Thanks in advance! - Todd
.
- References:
- capture output of an ldapmodify command
- From: Anton
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