Re: AWK problem need help

Akhil wrote:
Hi,
I am trying out an "AWK" script, to search and modify some pattern in
text file.
The script is as follows:

NR<100 {
if ( ( $6 ~ /^(x|X)/ ) || ( $4 ~ /^(x|X)/ ) ) {
printf ("PAT:%s\n", $prev)
print NR, $0
z = split($prev, lastline, " ")
if ( lastline[0] ~ /^\/\// ) {
print NR >> "bin/output.atp"
}
if ( lastline[0] ~ /repeat/ ) {
print NR, NR >> "bin/output.atp"
} else {
print NR, NR, NR >> "bin/output.atp"
}
} else {
print $0 >> "bin/output.atp"
prev = $0
}
}


My observation here is:
In else part (i.e. when I dont get the regx match, I am trying to
store the line read) in a variable, and I wnated to use it later. But
when I try printing the variable "prev" next time when I have "regx"
match, it displays the current line i.e. $0 itself

Please suggest some alternative to store the previously read line.

Akhil


awk is not shell. To print the value of an awk variable is "print var", not "print $var". The latter would print the field at whatever position "var" contains, and the whole record if var is zero or unset.

Also, you don't need the " " as the final argument to split() as that's the default, and awk arrays start at 1, not 0 so "lastline[0]" will always be empty.

Finally - are you sure you know what "print >> " does in awk? Again, awk is not shell...

Ed.
.

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