Re: bash: process substitution not working in script

On 4/29/2008 1:03 PM, lihao0129@xxxxxxxxx wrote:
I have a bash script which accept two input, one from a file, another
from the output of a shell pipeline. thought I can use process
substitution here, like:

awk -F'.' '
FNR == NR {
# do_sth();
next;
} {
# do_other_thing();
}
' file1.txt <( find -type f -exec file {}
+ | \
awk -F: '$2~/image/{split($1,b,"/");print
b[2]}' | \
sort -nk1 | uniq -
c' \
)

This works pretty well under command-line, but when I wrapped up
exactly the above lines into a shell script(since I need to test over
different directories), it did not work. the error shows:



./script.sh: line 30: syntax error near unexpected token `('
./script.sh: line 30: `' file1.txt <( find -type f -exec file {}
+ | \'

I checked the man page about the process substitution which mentioned
the named pipe. since I am not familiar with this part, could someone
help me with this problem? many thanks,


Since there's line-wrapping, etc. in your posting, it's hard to say what's
causing the problem, but in any case all you really need here is a pipeline:

find ... | awk ... | sort ... | uniq ... |
awk -F'.' '
FNR == NR {
# do_sth()
next
} {
# do_other_thing()
}
' file1.txt -

Note the "-" sign at the end to tell awk to read stdin after reading file1.txt.

Regards,

Ed.

.

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