Help with an awk command

Instead of going for a overly complicated grep/sed/stat/find commands, is there a way to use awk to break the file name into the required string groups in a single shot? yea I being lazy by asking.

Directory Files
rpm-12.3.4.5-10.x86_64.rpm
rpm1_1-1.0.0.8-1.noarch.rpm
rpm1_1-1.0.0.9-1.noarch.rpm (assuming later timestamps the the file above)
rpm3-next-1.2.3.4-1.noarch.rpm

Expected output (filename, version, arch)
rpm 12.3.4.5-10 x86_64
rpm1_1 1.0.0.9-1 noarch
rpm3-next 1.2.3.4-1 noarch

I was using "find *.rpm | sed 's/-[0-9].*//'" to get just the rpm name.

Thanks in advance
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